That's what I expected but didn't want to make any assumptions. 2A is a lot, even 30 years ago negligable crossover distortion was possible with only a few milliams of quiescant. I suspect this was a 'no holds barred' type thing especially when considered with separate transformers for each channel and frequency response down to DC. I suspect the fan required to cool the resulting furnace makes far more noise than the harmonics would have
In view of the value of the speakers in queston, it may be prudent to add a capacitor in series for future protection. If you roll off at about 5-10Hz I doubt you will hear, sorry feel, the difference. Your neighbours might though
. The downside is it will be a large capacitor and will need to be an unpolarised electrolytic or 2 conventional ones in series in opposing directions, each one double the required value. To calculate the value: C(farads) = 1/(2 x PI x F (Hz) x R (ohms)) so for 8ohm speaker and 10Hz C = 0.002F or 2,000uF (use 2x 4700uF in series with negatives connected to each other and ideally through about a 10K bleed to the negative rail to bias the capacitors)
Back to the original topic,
Measure the voltage across each power supply capacitor with a meter, they should all be about the same.
Using a scope with earth connected to the busbar on the capacitors, look at each power rail (you may need the scope on AC to see the ripple) The peaks of the ripple should be 10mS apart (100Hz). If it's 20mS then a diode will have gone in the rectumfriar.
If one has a lot more ripple (but correct frequency) it will either be capacitor gone high resistance or a lot more current being drawn from that rail.
_________________
If at first you don't suck seed, try drier grain.